<PRE><B>Question 371779</B>
A 30% acid solution is to be mixed with a 50% acid solution to get 100 milliliters of a 35% acid solution. How many milliliters of 30% are needed

Let x = the number of milliliters of 30% needed
100-x = the number of milliliters of 50% needed

0.30x + 0.50(100-x) = .35(100)
0.30x + 50 - 0.5x   = 35
            -0.2x   = 35-50
                x   = 75
             
75 milliliters of 30% are needed




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