Question 371646
A rectangle is twice as long as it is wide. If its length and width are each reduced by 1 inch, the area of the rectangle is reduced by 14 square inches. Find the dimensions of the original rectangle.

Let x = the width of the rectangle
   2x = the length of the rectangle

(x-1)(2x-1) = x(2x) - 14

Solve for x
2x^2-x-2x+1 = 2x^2 -14
Combine like terms
        -3x = -15
          x = 5
         2x = 10

The dimensions of the original rectabngle are
width = 5 inches
length= 10 inches