Question 371607
the given equation is 2x+y=10
re-write in slope intercept form
y=-2x+10
compare with equation
y = mx+b
slope m=-2
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the desired line is perpendicular to this line so slope is negative reciprocal of the given line
slope = 1/2
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passing through (-2,4)
y= mx+b
plug value of m x,y
4=1/2*-2+b
4=-1+b
b=5
so the line will be y = (1/2)x+5
{{{graph(300,300,-6,6,-1,10,(-2x+10),((x/2)+5)))}}}
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m.ananth@hotmail.ca