Question 5232
in the Lesson section on this site, i have written explanations on how to solve such systems. Have a look there, to learn.


Here is your solution: I shall pick to make the x terms the same:


2x+3y=10 by x3
-3x+2y=11 by x2


 6x+9y = 30
-6x+4y = 22


Now add the 2 equations together to give 13y = 52. Next,

y = 52/13
--> y = 4


so, now in 2x+3y = 10
--> 2x + 3(4) = 10
--> 2x + 12 = 10
--> 2x = -2
--> x = -1


Now check in other equation
-3x+2y
-3(-1) + 2(4)
3 + 8
11 --> which is the correct answer!


So, the solution is correct.


Jon.