Question 371437
Quadratic Formula   {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

a) {{{-2x^2-23x+6=3x^2+15x}}}  Need to get everything in the equation to one side and have it equal to 0.

{{{-5x^2-38x+6=0}}}  A quadratic equation is {{{ax^2+bx+c=0}}}
So a=-5 
   b=-38
   c=6    
Plug these values into the quadratic formula (above) and solve for x.  Remember there will be two values for x because of the + or -.

b) {{{(x+2)(x-3)=(2x-1)(x-4)}}}  Foil both sides then get everything to one side and set equal to 0.  

{{{x^2-x-6=2x^2-9x+4}}}
{{{-x^2+8x-10=0}}}

So a=-1
   b=8
   c=-10

Plug these into the Quadratic Formula and solve for x.