Question 371393
<pre>
{{{2x^2+3x+4=0}}}

Compare to

{{{ax^2+bx+c=0}}}

{{{a=2}}}, {{{b=3}}},  {{{c=4}}}

Sustitute those values in

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

{{{x = (-(3) +- sqrt( (3)^2-4*(2)*(4) ))/(2*(2)) }}}

{{{x = (-3 +- sqrt(9-32 ))/4 }}}

{{{x = (-3 +- sqrt(-23))/4 }}}

{{{x = (-3 +- i*sqrt(23))/4 }}}

Write as separate fractions:

{{{x = -3/4 +- expr(sqrt(23)/4)i }}}

Edwin</pre>