Question 371356
Let say particle 1 start at {{{x=0}}}.
Particle 2 starts at {{{x=300}}}meters.
{{{D[1]=0+1.5t}}}
{{{D[2]=300-3.5t}}}
Find {{{t}}} when {{{D[1]=D[2]}}}
{{{1.5t=300-3.5t}}}
{{{5t=300}}}
{{{t=60}}}sec
When {{{t=60}}},
{{{D[1]=D[2]=1.5(60)=90}}}m
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{{{drawing(300,300,-10,90,-50,300,circle(60,90,2.3),graph(300,300,-10,90,-50,300,0,1.5x,300-3.5x))}}}