Question 371345
how do i find the completion of squares for the equation 
y^2-5y+6=0
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y^2-5y+? = -6+?
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Complete the square:
y^2-5y+(5/2)^2 = -6+(5/2)^2
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Factor the left side:
(y-(5/2))^2 = (-24/4)+(25/4)
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(y-(5/2))^2 = = 1/4
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y-(5/2) = 1/2 or y-(5/2) = -1/2
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y = 3 or y = 2
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Cheers,
Stan H.