Question 371302
{{{f(x)=-x^2+x-3}}}
Complete the square to convert the equation to vertex form.
{{{f(x)=-(x^2-x)-3}}}
{{{f(x)=-(x^2-x+1/4)-3+1/4}}}
{{{f(x)=-(x-1/2)^2-12/4+1/4}}}
{{{f(x)=-(x-1/2)^2-11/4}}}
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({{{h}}},{{{k}}})=({{{1/2}}},{{{-11/4}}})
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{{{drawing(300,300,-5,5,-9,1,grid(1),circle(1/2,-11/4,0.2),graph(300,300,-5,5,-9,1,-x^2+x-3))}}}