Question 370906
{{{(2x^2 + 3x - 35)/(x + 5)}}}
Before we actually try to divide, let's see if this fraction will reduce. Reducing a fraction involves canceling common factors between the numerator and denominator. And to cancel common factors, we need to know what the factors are. So we start by factoring:
{{{((2x-7)(x+5))/(1*(x+5))}}}
We can now see that (x+5) is a factor which is common to the numerator and denominator. We can cancel them:
{{{((2x-7)cross((x+5)))/(1*cross((x+5)))}}}
leaving:
{{{(2x-7)/1}}}
And dividing by 1 is the easiest division of all! This simplifies to:
2x-7