Question 370734
First, we need to understand that synthetic division works for divisors of the form: (x - a) where "s" is some number. So we need to change (x+2) to be a subtraction: (x - (-2)).
Also it is important to represent every power of the variable when using synthetic division. So we will need a zero coefficient for the missing squared term. Putting these together we get:
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-2 |   5    0   6    8
          -10  20  -52
      ----------------
       5  -10  26  -44
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The number in the lower right corner is the remainder. As you may recall the remainder is put into the numerator of a fraction with the divisor in the denominator.
The rest of that bottom line is the rest of the quotient. So:
{{{(5x^3+6x+8)/(x+2) = 5x^2 -10x +26 + (-44)/(x+2)}}}
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