Question 371294
Problem: A bricklayer begins work at 7 a.m., laying 170 bricks per hour. Two hours later his apprentice joins him and lays 80 bricks per hour. At what time will they have laid 965 bricks?
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Apprentice DATA:
rate = 80 b/h ; time = x hrs ; work done = 80x bricks
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Bricklayer DATA:
rate = 170 b/h ; time = x+2; ; work done = 170(x+2) bricks
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Equation:
bricks + bricks = 965 bricks 
80x + 170(x+2) = 965
80x + 170x + 340 = 965
250x = 625
x = 2.5 hrs
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x+2 = 4.5 hrs
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Time: 7 am + 4.5 hrs = 11:30 am (time they finish the work)
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Cheers,
Stan H.