Question 371180
let one leg be x
other leg = x-1
hypotenuse = x+2
..
x^2+(x-1)^2=(x+2)^2
x^2+x^2-2x+1= x^2 +4x+4
x^2-6x-3=0
solve for x using quadratic formula
discriminant = 48
x1=((6+sqrt(48))/2
x1= 6.46cm one leg
other leg will be 5.46cm
hypotenuse = 7.46cm
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m.ananth@hotmail.ca