Question 370709
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Hi,
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
vertex (-3, 5)
y = a(x+3)^2 + 5
parabola passes through (-4, 6)
6 = a(-4+3)^2 + 5

6 = a + 5
1 = a
Equation of parabola:
y = 1*(x+3)^2 + 5  Or y =(x+3)^2 + 5
{{{drawing(300,300, -10, 4, -4, 10, grid(1),
graph( 300, 300,-10,4,-4,10,(x+3)^2 + 5)) }}}