Question 370569
let second pipe take x hours to fill
it will do 1/x of the job in 1 hour.
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First pipe takes 5 hour less than second pipe.
x-5 hours
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it can do 1/(x-5) of the job in 1hour.
... Together they do the job in 6 hours..
together they do 1/6 of the job in hour.
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1/x + 1/(x-5 ) = 1/6
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LCD = x(x-5)
(x-5+x)/(x(x-5))=1/6
(2x-5)/x(x-5) = 1/6
6(2x-5)=x(x-5)
12x-30=x^2-5x
x^2-5x-12x+30=0
x^2-17x+30=0

x^2-15x-2x+30=0
x(x-15)-2(x-15)=0
(x-15)(x-2)=0
x= 2 OR 15 hours
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m.ananth@hotmail.ca