Question 370545
having trouble graphing the following parabola:

x = 2y^2
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Solve for "y":

y^2 = x/2

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y = +/-sqrt(x/2)
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Plotting points:
Let x = 0, they y = 0
Let x = 8, then y = +2 and y = -2
Let x = 32, then y = +4 and y = -4
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Plot the points: (0,0), (8,2), (8,-2), (32,4), (32,-4)
and draw a parabola that opens to the right.
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Cheers,
Stan H.