Question 370510
Solve algebraically giving answers in terms of π: 
2sinx=1, 0 ≤ x ≤ 6π
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sin(x) = 1/2,
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Since x is limited to 0<= x <= 6*pi
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x = (pi/6)+ 2n(pi) where n = 0,1,2
or
x = (5/6)pi + 2n(pi) where n = 0,1,2
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Cheers,
Stan H.