Question 370383
This maths homework is killing me. 
f(x)=-x^2+6x+16 
a) Write f(x) in the form a(x+b)^2+c where they are constants. State the max value of f(x).
-x^2+6x+16 = y
-x^2+6x = y-16
-(x^2-6x+?) = y-16-?
-(x^2-6x+9) = y-16-9
-(x-3)^2 = y-25
y = -(x-3)^2 + 25
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Since the parabola opens downward, max occurs at the vertex
Vertex: (3,25)
Max value = 25
{{{graph(400,300,-10,10,-10,40,-x^2+6x+16)}}}
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b) Solve f(x)=0 and sketch the curve y=f(x).
Solve: -x^2+6x+16 = 0
x = [-6 +- sqrt(36-4*-1*16)]/-2
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 What are the coordinates where the curve meets the x and the y axes? and the coordinates of the max or min points?
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Cheers,
Stan H.