Question 370382
find two consecutive odd integers such that five times the first integer is 25 less than twice the greater integer
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1st: 2x-1
2nd: 2x+1
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Equation:
5(2x-1) = 2(2x+1)-25
10x-5 = 4x+2-25
6x = -18
x = -3
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1st: 2x-1 = -7
2nd: 2x+1 = -5
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Cheers,
Stan H.
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