Question 370196
{{{F=P(1+r)^t}}}
{{{r=0.02/4=0.005}}}
{{{600=500(1+0.005)^t}}}
{{{(1.005)^t=6/5}}}
{{{highlight(t=log(1.005,(6/5)))}}}
{{{t=log(10,(6/5))/log(10,(1.005))}}}
or approximately,
{{{t=36.554}}}
Rounding up that would be {{{37}}} quarters.