Question 370167
{{{3x^2+8x-3=(x+3)(3x-1)}}}
{{{3x^2-7x+2=(3x-1)(x-2)}}}
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Use a common denominator, {{{(x+3)(x-2)(3x-1)}}}
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{{{2/(3x^2+8x-3)=2/((x+3)(3x-1))=(2(x-2))/((x-2)(x+3)(3x-1))}}}
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{{{1/(3x^2-7x+2)=1/((3x-1)(x-2))=(x+3)/((x+3)(x-2)(3x-1))}}}
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{{{2/(3x^2+8x-3)+1/(3x^2-7x+2)=(2(x-2))/((x-2)(x+3)(3x-1))+(x+3)/((x+3)(x-2)(3x-1))}}}
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{{{2/(3x^2+8x-3)+1/(3x^2-7x+2)=(2(x-2)+x+3)/((x+3)(x-2)(3x-1))}}}
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{{{2/(3x^2+8x-3)+1/(3x^2-7x+2)=(2x-4+x+3)/((x+3)(x-2)(3x-1))}}}
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{{{2/(3x^2+8x-3)+1/(3x^2-7x+2)=(3x-1)/((x+3)(x-2)(3x-1))}}}
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{{{2/(3x^2+8x-3)+1/(3x^2-7x+2)=highlight(1/((x+3)(x-2)))}}}