Question 370127
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Hi,
w^4 - 6u^2 - 2 = 0 
using the Pythagorean Theorem to solve for w^2
{{{w^2 = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{w^2 = (6 +- sqrt( 44 ))/(2) }}}
{{{w^2 = (6 +- 2*sqrt(11))/(2) }}}
{{{w^2 = (3+- sqrt(11))}}}
w^2 = 3 + 3.317 = 6.317
w = 2.512
w = -2.513
w^2 = 3 - 3.317 = -.317
w = .563*i
w = -.563*i