Question 370066
I'll do one, you do the rest.
{{{a=-2}}}
Substitute for {{{-2}}} wherever there is an {{{a}}}.
{{{(5a^5-2a^3-9a^2)=5(-2)^5-2(-2)^3-9(-2)^2}}}
{{{(5a^5-2a^3-9a^2)=5(-32)-2(-8)-9(4)}}}
{{{(5a^5-2a^3-9a^2)=-160+16-36}}}
{{{(5a^5-2a^3-9a^2)=highlight(-180)}}}
Follow the same procedure for the other polynomials.