Question 370005
 race distance = 3 & back

A = 20 mph
B= 16 mph
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A takes 3/20 hour to reach other end

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By then
B has reached 16*3/20 miles
=12/5 miles
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at this point of time  they are 3-(12/5) miles apart facing each other.
=3/5 miles.
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Now they are running towards each other
their speeds when added up is 36 mph
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distance = 3/5 miles
speed = 36 mph
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time they meet = (3/5) /36
3/5 *1/36
=3/180  hours.
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in 3/180 hours B will run ( d= rt)
3/180 * 20 
=1/3 mile
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1/3 * 5280 = 1760 feet  from the returning end.
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m.ananth@hotmail.ca