<PRE><B>Question 369901</B>
2+3i 7-2i
---- + ----
3-2i 8+i 
-----------
Step 1, get the i&#39;s out of the denominators.  Multiply NUM and DEN by the conjugate of the DEN
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(2+3i)*(3+2i)  (7-2i)*(8-i)
------------- + -----------
(3-2i)*(3+2i)  (8+i)*(8-i) 
---
(6+13i-6)   (56 - 23i - 2)
--------- + -----------
(9 + 4)         (64 + 1) 
---
13i   (54 - 23i)
--- + ----------
13        65
= (54 - 23i)/65 + i
= (54 - 23i)/65 + 65i/65
= (54 + 42i)/65
</PRE>