Question 369665
1.{{{A*B=442}}}
2.{{{A+B=43}}}
From eq. 2,
{{{A=43-B}}}
Substitute into eq. 1,
{{{(43-B)B=442}}}
{{{-B^2+43B=442}}}
{{{B^2-43B+442=0}}}
Factor,
{{{(B-26)(B-17)=0}}}
Two solutions:
{{{B-26=0}}}
{{{B=26}}}.
.
.
.
{{{B-17=0}}}
{{{B=17}}}
Then,
{{{A=43-B=26}}}
{{{B=17}}}
.
.
{{{A=43-B=17}}}
{{{B=26}}}
The two numbers are 17 and 26.