Question 369586
Let the angle be x and its complement be c, then:
{{{x=c+10}}} and {{{x+c=90}}}.
In the second equation, substitute x for {{{c+10}}}:
{{{c+(c+10)=90}}}
Now, solve:
{{{c+(c+10)=90}}}
{{{c+c+10=90}}}
{{{2c+10=90}}}
{{{2c=80}}}
{{{c=40}}}
 
Now, in the first equation, substitute c for 40:
{{{x=40+10}}}
{{{x=50}}}
 
So, the measure of the angle is 50°, and the measure of its complement is 40°.