Question 369560
Let the first number be x and the second number be y, then:
{{{2x+3y=41}}} and {{{x-y=8}}}
 
The easiest way to solve this is to multiply the second equation by 3:
{{{3x-3y=24}}}
Now, add the equations:
{{{2x+3y+3x-3y=41+24}}}
Combine like terms:
{{{5x=65}}}
Divide both sides by 5 to simplify:
{{{x=13}}}
 
Now, substitute 13 for each x in one of the original equations. In this case, the second equation will be easier.
{{{13-y=8}}}
Add y to each side:
{{{13=y+8}}}
Subtract 8 from each side:
{{{5=y}}}
{{{y=5}}}
 
So, {{{x=13}}} and {{{y=5}}}.