Question 369450
8 years ago, Jimmy was 3 times as old as Anne. In 4 years, Jimmy will be 3/2 of Anne's age. What is each ages?

Let J = age of Jimmy
    A = age of Anne

1st equation
J- 8 = 3(A -8)
J- 8 = 3A -24
J-3A = -16

2nd equation
J + 4 = 3/2(A+4)
J + 4 = 1.5A + 6
J - 1.5A = 2

Deduct the 1st equation from the 2nd equation

(J-J) -1.5-(-3A) = 2-(-16)
            1.5A = 18
               A = 12

Substitute The value of A in equation1 to solve for J
J - 3(12) = -16
        J = 36-16
        J = 20

Anne is 12 years old and Jimmy is 20 years old.