Question 369161
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For each of the 9 appetizers there are 11 ways to select the entrée for 9 times 11 equals 99 ways to select the appetizer and entrée. Then for each of those 99 ways, there are 9 ways to select the dessert, 99 times 9 = 891.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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