<PRE><B>Question 369116</B>
The easiest way is by substitution. &lt;br&gt;

y=3x&lt;br&gt;

3x+4y=30&lt;br&gt;

Since we know what y equals in the first equation (3x), we will substitute that in for the value of y in the second equation.&lt;br&gt;

So we now have&lt;br&gt;

3x+4*(3x)=30&lt;br&gt;

3x+12x=30&lt;br&gt;

15x=30&lt;br&gt;

x=2&lt;br&gt;

Since we know what x has to be, we can just substitute that value into either equation to find the value of y.&lt;br&gt;

y=3x&lt;br&gt;

y=3*2&lt;br&gt;

y=6&lt;br&gt;

&lt;b&gt;The solution to this system of equations is x=2 and y=6, or the point (6,2)&lt;/b&gt;&lt;br&gt;

When dealing with a system of 2 linear equations, the solution to the system will always be a singe point, unless the two lines are parallel or are actually the same line.  :)&lt;br&gt;

I hope this helps!&lt;br&gt;</PRE>