Question 369027
If you started with:
{{{ 16^(3/2)=64 }}} 
taking log base 16 of both sides:
{{{ 3/2 = log(16,64) }}}
{{{ 3/2 = log(64)/log(16) }}}
cross multiplying
{{{ 3*log(16) = 2*log(64) }}}
...
easier way would be to:
{{{ 16^(3/2)=64 }}} 
{{{ sqrt(16^3)=64 }}} 
{{{ sqrt(16*16*16)=64 }}} 
{{{ 16*sqrt(16)=64 }}} 
{{{ 16*sqrt(4*4)=64 }}} 
{{{ 16*4=64 }}} 
{{{ 64=64 }}}