Question 369020
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Hi
vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex

f(x)=-2x^2-4x-3
f(x)=-2[x^2+2x + 3/2]
f(x)=-2[x^2+2x +1  -1 +3/2]
f(x)=-2[(x+1)^2   -1 +3/2]
f(x)=-2(x+1)^2  -2( -1 +3/2)
f(x)=-2(x+1)^2 + 2 - 3
f(x)=-2(x+1)^2 -1 
(-1, -1) is the vertex 
{{{graph( 300, 300,-6,6,-6,6,-2x^2 -4x -3) }}}