Question 368948
Use polynomial long division,
{{{(x+3)(x-4)=x^2-x-12}}}
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<pre>

           x^2 + 4x + 14
         __________________________________
x^2-x-12 | x^4 + 3x^3 -  2x^2 +  0x +   1
      -   (x^4 -  x^3 - 12x^2)
          --------------------
                 4x^3 + 10x^2
             -  (4x^3 -  4x^2 - 48x)
                --------------------
                        14x^2 + 48x +   1
                     - (14x^2 - 14x - 168)
                       -------------------
                                62x + 169
                               
</pre>
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Average is the sum of total scores divided by total number of scores.
{{{(x^4+3x^3-2x^2+1)/((x+3)(x-4))=(x^2+4x+14)+(62x+169)/((x+3)(x-4))}}}