Question 368748
Simplify first.
{{{(4x^2+20x+25)/(4x^2-25)=(2x+5)^2/((2x+5)(2x-5))= (2x+5)/(2x-5) }}}
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{{{1/(2x^2-11x+15)=1/((2x-5)(x-3))}}}
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{{{((4x^2+20x+25)/(4x^2-25))/(1/(2x^2-11x+15))=((2x+5)/(2x-5))*((2x-5)(x-3))}}}
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{{{((4x^2+20x+25)/(4x^2-25))/(1/(2x^2-11x+15))=highlight((2x+5)(x-3))}}}