Question 368787
{{{graph(300,300,-2,6,-2,6,0,e^(x),1/x)}}}
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{{{A=int((e^(x)-1/x),dx,2,4)=e^x-ln(x)+C}}}
{{{A=e^(4)-e^(2)+ln(4)-ln(2)}}}
{{{highlight(A=e^(4)-e^(2)+ln(2))}}}