Question 368790
Let {{{u=4t^2-1}}}
then {{{du=8tdt}}}
{{{int(6t(4t^2-1)^9,dt)=int(6u^9(1/8),du)}}}
{{{int(6t(4t^2-1)^9,dt)=(6/8)(u^10/10)+C}}}
{{{int(6t(4t^2-1)^9,dt)=highlight((3/40)(4t^2-1)^10+C)}}}