Question 368791
Let's see...the two figures intersect at (0,3) and at (7,52)...we have to integrate the difference of the functions from x = 0 to x = 7, so we have

Area = Integral from 0 to 7 of {{{7x + 3 - (x^2 + 3)}}}
= Integral from 0 to 7 of (7x - x^2)
= {{{(7/2)x^2 - (1/3)x^3)}}} evaluated from 0 to 7...
= {{{(7/2)(49) - (1/3)(343)}}}