Question 368840
2x+4y=-10;(4,2)
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2x+4y=-10
/2
x+2y=5
-x
2y+x-x=-x+5
2y=-x+5
/2
y=(-1/2)x+5/2
slope = (-1/2)
..
the slope perpendicular to this line will have a negative reciprocal as slope
=2
..
The new line passes through ;(4,2)
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equation of line = (y-4)=2(x-2)
y-4=2x-4
y=2x
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{{{graph(300,300,-5,5,-5,5,((-x/2)+(5/2)),2x)}}}
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