Question 368826
If their slopes are negative reciprocals, they are perpendicular...let's find the slopes of
y=8x-8

2y=5-x

Using y = mx + b, the first has a slope of 8, and solving the second for y, we get
{{{y = (-1/2)x + 5/2}}}
and its slope is -1/2.

Thus these are not perpendicular.