<PRE><B>Question 368737</B>
Write an equation for the line perpendicukar to MN that contains point P. 
MN:y=2/3x, P(6,6)
Slope of given the given line is 2/3
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The slope of lines perpendicular is the negative inverse, = -3/2
Use y = mx + b and the point to find b, the y-intercept.
6 = (-3/2)*6 + b
b = 15
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--&gt; y = (-3/2)x + 15
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so than the book tells me to put it into a equation like:
2/3m=-1 
I get that but how do I get 2/3 to the other side 
2/3m=-1
I think I divide the 2/3 on both side to get rid of it on the m side but how do I multiply 2/3 by -1? 
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