<PRE><B>Question 368714</B>
Let x be the first integer.  The next 3 consecutive integers will be: &lt;br&gt;

x+1, x+2, and x+3&lt;br&gt;

Thus, we know&lt;br&gt;

x+(x+1)+(x+2)+(x+3)=250&lt;br&gt;

4x+6=250&lt;br&gt;

4x=244&lt;br&gt;

x=61&lt;br&gt;

&lt;b&gt;Thus, the four integers are 61, 62, 63, and 64!&lt;/b&gt;&lt;br&gt;

I hope this helps!&lt;br&gt;</PRE>