Question 368388
Find both values for t when s=192.
{{{s=-16t^2+208t+0=192}}}
{{{16t^2-208t+192=0}}}
{{{t^2-13t+12=0}}}
{{{(t-12)(t-1)=0}}}
Clearly the two solutions are {{{t=1}}} and {{{t=12}}}.
{{{DELTA*t=12-1=highlight(11)}}}seconds.