Question 368282
{{{drawing(300,300,-1,5,-3,3,circle(3.404,0.9396,0.12),graph(300,300,-1,5,-3,3,0,(11.4-2.3x)/3.8,(3.1)ln(x - 2.05)))}}}
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I used Newton's method to find the root with a starting value of {{{x=3}}}.
{{{x=3.404065}}}
{{{y=0.939645}}}