Question 40840
Well if the volume of a rectangular box is given as
V = (x^2 + 5x + 6)(x + 5)
we can factor that to get
V = (x + 2)(x + 3)(x + 5)
so that any two of these three can be the length or width and third would be the height...it's an ambiguous problem...
The product of any two could represent the area of the base...