Question 368329
A chemist is mixing a 11% acidic solution with a 6% acidic solution  to obtain 600 mL of an 8% acidic solution. How much of each must he have?

Let x = the amount of 11% acidic solution

600-x = the amount of 6% acidic solution

.11x + .06(600-x) = .08(600)
.11x + 36 - .06x  = 48
            .05x  = 12
               x = 240

         600 - x = 360

The chemist must have 240 mL of 11% acidic solution and 360 mL of 6% acidic solution.