Question 368255
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The area of a triangle is calculated by *[tex \Large A\ =\ \frac{bh}{2}]


But since your base is 9 feet longer than the height, and the area is 68, you can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{b(b\ -\ 9)}{2}\ =\ 68]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b^2\ -\ 9b\ -\ 136\ =\ 0]


Solve the quadratic for the positive root.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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