Question 40841
Jeff leaves his house on his bicycle at 8:30 A.M. and averages 5 miles per hour. His wife, Joan, leaves at 9:00 A.M. following the same path and averaging 8 miles per hour. At what time will Joan catch up with Jeff?

Jeff Data:
Distance=?; Rate=5mph ; Time=x hrs.

Joan Data:
Distance=?; Rate=8 mph; Time=x-1/2 hrs.

EQUATIon:
Jeff distance = Joan distance
 5x=8(x-1/2)
5x=8x-4
-3x=-4
x=4/3 hrs. = 80 minutes

Cheers,
Stan H.