Question 368023
log(x^4) - log(x^3)+log2 = log(6-x).
log(x^4/x^3)+log2 = log(6-x),
logx+log2 = log(6-x),
log(2x) = log(6-x),
2x = 6-x, since log is a 1-to-1 function.  Hence
3x = 6,
x = 2.  This satisfies the original equation, and thus is the final answer.