Question 367889
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Step 1:  With respect to your given equation, divide the negative of the coefficient on *[tex \Large x] by the coefficient on *[tex \Large y].  The result is the slope of the graph of the given equation.


Step 2:  Calculate the negative reciprocal of the slope from step 1.  This is the slope of the desired line.  That is because the slopes of perpendicular lines are negative reciprocals, that is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


Step 3:  Use the point-slope form of an equation of a line two write your desired equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the slope calculated in step 2.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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